CCF_100/relational
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i need to reduce sets, so i need selection pushed down in each case

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git-svn-id: http://galileo.dmi.unict.it/svn/relational/trunk@143 014f5005-505e-4b48-8d0a-63407b615a7c
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LtWorf 2009-04-30 17:41:05 +00:00
parent 723c63641d
commit 88efcf0b78
1 changed files with 6 additions and 13 deletions
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19
relational/optimizations.py
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@ -46,11 +46,7 @@ def duplicated_select(n):
def down_to_unions_subtractions_intersections(n): def down_to_unions_subtractions_intersections(n):
'''This funcion locates things like σ i==2 (c ᑌ d), where the union '''This funcion locates things like σ i==2 (c ᑌ d), where the union
can be a subtraction and an intersection and replaces them with can be a subtraction and an intersection and replaces them with
σ i==2 (c) ᑌ σ i==2(d). σ i==2 (c) ᑌ σ i==2(d).
If the operator is not Union and the right expression is a relation,
the resulting expression will be: σ i==2 (c) - d.
''' '''
changes=0 changes=0
_o=('ᑌ','-','ᑎ') _o=('ᑌ','-','ᑎ')
@ -61,14 +57,11 @@ def down_to_unions_subtractions_intersections(n):
left.name=n.name left.name=n.name
left.child=n.child.left left.child=n.child.left
left.kind=optimizer.UNARY left.kind=optimizer.UNARY
if n.child.name=='ᑌ' or n.child.right.kind!=optimizer.RELATION: right=optimizer.node()
right=optimizer.node() right.prop=n.prop
right.prop=n.prop right.name=n.name
right.name=n.name right.child=n.child.right
right.child=n.child.right right.kind=optimizer.UNARY
right.kind=optimizer.UNARY
else:
right=n.child.right
n.name=n.child.name n.name=n.child.name
n.left=left n.left=left