- Can perform survey from command line interface too

- Module to send survey directly
- Can check the latest version from the svn repository



git-svn-id: http://galileo.dmi.unict.it/svn/relational/trunk@311 014f5005-505e-4b48-8d0a-63407b615a7c

relational/maintenance.py

@@ -0,0 +1,57 @@
+# -*- coding: utf-8 -*-
+# Relational
+# Copyright (C) 2008  Salvo "LtWorf" Tomaselli
+# 
+# Relation is free software: you can redistribute it and/or modify
+# it under the terms of the GNU General Public License as published by
+# the Free Software Foundation, either version 3 of the License, or
+# (at your option) any later version.
+# 
+# This program is distributed in the hope that it will be useful,
+# but WITHOUT ANY WARRANTY; without even the implied warranty of
+# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+# GNU General Public License for more details.
+# 
+# You should have received a copy of the GNU General Public License
+# along with this program.  If not, see <http://www.gnu.org/licenses/>.
+# 
+# author Salvo "LtWorf" Tomaselli <tiposchi@tiscali.it>
+#
+# Stuff non-related to relational algebra, but used for maintenance.
+
+import httplib
+import urllib
+
+def send_survey(data):
+    '''Sends the survey. Data must be a dictionary.
+    returns the http response'''
+    
+    post=''
+    for i in data.keys():
+        post+='%s: %s\n' %(i,data[i])
+    
+    #sends the string
+    params = urllib.urlencode({'survey':post})
+    headers = {"Content-type": "application/x-www-form-urlencoded","Accept": "text/plain"}
+    connection = httplib.HTTPConnection('galileo.dmi.unict.it')
+    connection.request("POST","/~ltworf/survey.php",params,headers)
+    return connection.getresponse()
+
+
+def check_latest_version():
+    '''Returns the latest version available.
+    Heavely dependent on server and server configurations
+    not granted to work forever.'''
+    connection = httplib.HTTPConnection('galileo.dmi.unict.it')
+    connection.request("GET","/svn/relational/tags/")
+    r=connection.getresponse()
+    
+    #html
+    s=r.read()
+    
+    l= s[s.find('<ul>')+4:s.find('</ul>')].split('\n')
+    l.sort()
+    a=l[len(l)-1]
+    
+    s=a.find('"')+1
+    return a[s:a.find('"',s)-1]