relational/parser.py
2008-07-20 22:10:35 +00:00

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# coding=UTF-8
# Relation
# Copyright (C) 2008 Salvo "LtWorf" Tomaselli
#
# Relation is free software: you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
#
# author Salvo "LtWorf" Tomaselli <tiposchi@tiscali.it>
def parse(expr):
'''This function parses a relational algebra expression, converting it into python,
executable by eval function to get the result of the expression.'''
symbols=("σ","π","ρ")
expr=expr.strip()
print "====PARSING: ",expr
start=-1
end=-1
parenthesis=0
lexpr=list(expr)
#Parses the string from end to begin
for i in range(len(lexpr)):
if lexpr[i]=="(":
if parenthesis==0:
start=i+1
parenthesis+=1
elif lexpr[i]==")":
parenthesis-=1
if parenthesis==0:
end=i
break
if start==-1: #No complex operators
return parse_op(expr)
else:
#internal=expr[0:start]+ parse(expr[start:end])+expr[end:]
internal=parse(expr[start:end])
print "EXPRESSION: %s" % (internal)
endp=start-1
start=-1
symbol=""
for i in range(endp,-1,-1):
if expr[i:i+2] in symbols:
symbol=expr[i:i+2]
start=i+2
break
parameters=expr[start:endp]
print "===Internal: %s\t Parameters: %s" %(internal,parameters)
res=""
if symbol=="π":#Projection
params=""
count=0
for i in parameters.split(","):
if count!=0:
params+=","
else:
count=1
params+="\"%s\"" % (i.strip())
res="%s.projection(%s)" % (internal,params)
elif symbol== "σ": #Selection
res="%s.selection(\"%s\")" % (internal,parameters)
elif symbol=="ρ": #Rename
params=parameters.replace(",","\",\"").replace("","\",\"")
res="%s.rename(\"%s\")" % (internal,params)
print res
res= ("%s%s%s") % (expr[0:start-2],res.replace(" ",""),expr[end+1:])
return parse_op(res)
#Selection σage > 25 Λ rank = weight(A)
#Projection Q ᐅᐊ π a,b(A) ᐅᐊ B
#Rename ρid➡i,name➡n(A)
#π a,b(π a,b(A))
#ρid➡i,name➡n(π a,b(A))
#A ᐅᐊ B
def parse_op(expr):
'''This function parses a relational algebra expression including only operators
(not functions) and no parenthesis, converting it into python,
executable by eval function to get the result of the expression.'''
result=""
symbols={}
symbols["*"]=".product(%s)"
symbols["-"]=".difference(%s)"
symbols[""]=".union(%s)"
symbols[""]=".intersection(%s)"
symbols["ᐅᐊ"]=".join(%s)"
symbols["ᐅᐊLEFT"]=".outer_left(%s)"
symbols["ᐅᐊRIGHT"]=".outer_right(%s)"
symbols["ᐅᐊFULL"]=".outer(%s)"
for i in symbols:
expr=expr.replace(i,"_____%s_____"% (i))
tokens=expr.split("_____")
i=0;
tk_l=len(tokens)
while i<tk_l:
if tokens[i] not in symbols:
result+=tokens[i].strip()
else:
result+=symbols[tokens[i]] % (tokens[i+1].strip())
i+=1
i+=1
return result
if __name__=="__main__":
while True:
e=raw_input("Expression: ")
print parse(e)